What is the derivative of q(t)=6t^2+5t+4 ?

The derivative of q(t)=6t^2+5t+4 is 12t+5

What is the first derivative of q(t)=6t^2+5t+4 ?

The first derivative of q(t)=6t^2+5t+4 is 12t+5

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derivative of

q (t) = 6 t^{2} + 5 t + 4

12 t + 5

Solution steps

\frac{d}{d t} (6 t^{2} + 5 t + 4)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d t} (6 t^{2}) + \frac{d}{d t} (5 t) + \frac{d}{d t} (4)

\frac{d}{d t} (6 t^{2}) = 12 t

\frac{d}{d t} (5 t) = 5

\frac{d}{d t} (4) = 0

= 12 t + 5 + 0

Simplify

= 12 t + 5

\frac{5}{( 1 + 3 x )}

\frac{d}{d t} (- 38 t + 220)

(x^{2} + 9) (x^{3} + 5)

\frac{( x ^{4} + 9 )}{x ^{2}}

tan^{- 2} (x)

What is the derivative of q(t)=6t^2+5t+4 ?
The derivative of q(t)=6t^2+5t+4 is 12t+5
What is the first derivative of q(t)=6t^2+5t+4 ?
The first derivative of q(t)=6t^2+5t+4 is 12t+5