What is the first d/(df)(f(1)+f(-2)) ?

The first d/(df)(f(1)+f(-2)) is -1

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d/(df)(f(1)+f(-2))

\frac{d}{df} (f (1) + f (- 2))

- 1

Solution steps

\frac{d}{df} (f (1) + f (- 2))

Simplify

f (1) + f (- 2) : - f

= \frac{d}{df} (- f)

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= - \frac{df}{df}

Apply the common derivative:

\frac{df}{df} = 1

= - 1

y = lo g_{10} (sin^{2} (x))

sin^{54} (x) + tan^{37} (x)

\frac{sin ^{3} ( x )}{ln ( x ^{3} )}

\frac{sin ^{2} ( x )}{x}

\frac{d}{d t} (3 t^{3} - 2 t^{2} + t - 5)