What is the first (e^{-3}t)^' ?

The first (e^{-3}t)^' is 1/(e^3)

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(e^{-3}t)^'

(e^{- 3} t)^{^{'}}

\frac{1}{e ^{3}}

Decimal

0.04978 \dots

Solution steps

(e^{- 3} t)^{'}

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= e^{- 3} t^{^{'}}

Apply the common derivative:

t^{'} = 1

= e^{- 3} \cdot 1

Simplify

e^{- 3} \cdot 1 : \frac{1}{e ^{3}}

= \frac{1}{e ^{3}}

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