What is the derivative of x^3y^4 ?

The derivative of x^3y^4 is 3x^2y^4

What is the first derivative of x^3y^4 ?

The first derivative of x^3y^4 is 3x^2y^4

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derivative of

x^{3} y^{4}

3 x^{2} y^{4}

Solution steps

\frac{d}{d x} (x^{3} y^{4})

Treat

y

as a constant

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= y^{4} \frac{d}{d x} (x^{3})

Apply the Power Rule:

\frac{d}{d x} (x^{a}) = a \cdot x^{a - 1}

= y^{4} \cdot 3 x^{3 - 1}

Simplify

= 3 x^{2} y^{4}

d er i v a t i v e y = sin (x^{2} + 2 x + 3)

\frac{d}{d o} (5^{c} os x)

d er i v a t i v e t^{\frac{1}{4}}

\frac{d}{d r} (r^{3} - r^{2})

d er i v a t i v e x = 5 t^{2} - 2 t + 7

What is the derivative of x^3y^4 ?
The derivative of x^3y^4 is 3x^2y^4
What is the first derivative of x^3y^4 ?
The first derivative of x^3y^4 is 3x^2y^4