What is the integral of x/(y^2) ?

The integral of x/(y^2) is (x^2)/(2y^2)+C

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integral of x/(y^2)

integral

\frac{x}{y ^{2}}

\frac{x ^{2}}{2 y ^{2}} + C

Solution steps

\int \frac{x}{y ^{2}} d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= \frac{1}{y ^{2}} \cdot \int x d x

Apply the Power Rule

: \frac{x ^{2}}{2}

= \frac{1}{y ^{2}} \cdot \frac{x ^{2}}{2}

Simplify

\frac{1}{y ^{2}} \cdot \frac{x ^{2}}{2} : \frac{x ^{2}}{2 y ^{2}}

= \frac{x ^{2}}{2 y ^{2}}

Add a constant to the solution

= \frac{x ^{2}}{2 y ^{2}} + C

r^{2} - x^{2}

\frac{x ^{2} + 1}{x}

\frac{2 + e ^{x}}{e ^{x}}

\frac{sin ^{2} ( x )}{e ^{x}}

\frac{1}{x ^{3} \cdot ( e ^{- \frac{1}{x}} )}