(d^2+1)y=e^{2x+3}

Lösung

(d^{2} + 1) y = e^{2 x + 3}

y = c_{1} cos (x) + c_{2} sin (x) + \frac{e ^{3}}{5} e^{2 x}

Schritte zur Lösung

(d^{2} + 1) y = e^{2 x + 3}

Solve linear ODE:

y = c_{1} cos (x) + c_{2} sin (x) + \frac{e ^{3}}{5} e^{2 x}

y = c_{1} cos (x) + c_{2} sin (x) + \frac{e ^{3}}{5} e^{2 x}

(d^{2} + 4) y = cos^{2} (x)

y^{^{''}} - y = \frac{2}{( 1 + e ^{x} )}

(d^{2} + 3 d + 2) \cdot y = sin (x)

(d^{2} + 1) y = tan (x)

(d^{2} - 3 d + 2) \cdot y = 3 sin (x)