y^'= 1/(e^y+2)

Lösung

y^{^{'}} = \frac{1}{e ^{y} + 2}

y = - W (\frac{1}{2 e ^{\frac{- t - c _{1}}{2}}}) + \frac{1}{2} (t + c_{1})

Schritte zur Lösung

y^{'} (t) = \frac{1}{e ^{y} + 2}

Solve separable ODE:

y = - W (\frac{1}{2 e ^{\frac{- t - c _{1}}{2}}}) + \frac{1}{2} (t + c_{1})

y = - W (\frac{1}{2 e ^{\frac{- t - c _{1}}{2}}}) + \frac{1}{2} (t + c_{1})

f^{^{'}} (x) [2 - x] = f (x)

y^{^{'}} y = x - 3 - 6 cos (x)

\frac{e ^{- 1}}{2} \cdot y^{3} + x^{2} \cdot y^{2} \cdot y^{^{'}} = 0

x y^{^{'}} - y^{2} - y = 0

y + y^{^{'}} - 6 y = 0