y^'+6y^'+9y=0

Lösung

y^{^{'}} + 6 y^{^{'}} + 9 y = 0

y = e^{\frac{- 9 t + c _{1}}{7}}

Schritte zur Lösung

y^{'} (t) + 6 y^{'} (t) + 9 y = 0

Solve separable ODE:

y = e^{\frac{- 9 t + c _{1}}{7}}

y = e^{\frac{- 9 t + c _{1}}{7}}

(\frac{x + 2}{x}) y^{^{'}} = (\frac{2}{x}) y

y^{^{'}} = - (\frac{1}{x}) y

(x + 4) y^{^{'}} = y + 5

y^{^{''}} = x^{5} + x^{3} - sin (x)

f^{^{''}} (x) = 6 x^{3} x^{2}