f^'(x)=x^{1/x}

Lösung

f^{^{'}} (x) = x^{\frac{1}{x}}

f (x) = \int x^{\frac{1}{x}} d x

Schritte zur Lösung

f^{'} (x) = x^{\frac{1}{x}}

Wenn

f^{^{'}} (x) = g (x)

dann

f (x) = \int g (x) d x

f (x) = \int x^{\frac{1}{x}} d x

f (x) = \int x^{\frac{1}{x}} d x

18 x + y^{^{'}} = 20, - 3 x y (1) = 2

2 y^{^{'}} = \frac{( 1 - sin ( x ) ) ^{- 1}}{2}

f^{^{'}} (t) = e^{- t} \cdot (8 - 8 t)

y^{^{'''}} = x^{4}

y^{^{'}} - e^{4} x = 0