What is the integral of 2e^{5sin(3x)}cos(3x) ?

The integral of 2e^{5sin(3x)}cos(3x) is 2/15 e^{5sin(3x)}+C

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integral of 2e^{5sin(3x)}cos(3x)

\int 2 e^{5 s i n (3 x)} cos (3 x) d x

\frac{2}{15} e^{5 s i n (3 x)} + C

Solution steps

\int 2 e^{5 s i n (3 x)} cos (3 x) d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 2 \cdot \int e^{5 s i n (3 x)} cos (3 x) d x

Apply u-substitution

: \int e^{5 s i n (u)} cos (u) \frac{1}{3} d u

= 2 \cdot \int e^{5 s i n (u)} cos (u) \frac{1}{3} d u

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 2 \cdot \frac{1}{3} \cdot \int e^{5 s i n (u)} cos (u) d u

Apply u-substitution

: \int \frac{e ^{v}}{5} d v

= 2 \cdot \frac{1}{3} \cdot \int \frac{e ^{v}}{5} d v

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 2 \cdot \frac{1}{3} \cdot \frac{1}{5} \cdot \int e^{v} d v

Use the common integral:

\int e^{v} d v = e^{v}

= 2 \cdot \frac{1}{3} \cdot \frac{1}{5} e^{v}

Substitute back

= 2 \cdot \frac{1}{3} \cdot \frac{1}{5} e^{5 s i n (3 x)}

Simplify

2 \cdot \frac{1}{3} \cdot \frac{1}{5} e^{5 s i n (3 x)} : \frac{2}{15} e^{5 s i n (3 x)}

= \frac{2}{15} e^{5 s i n (3 x)}

Add a constant to the solution

= \frac{2}{15} e^{5 s i n (3 x)} + C

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What is the integral of 2e^{5sin(3x)}cos(3x) ?
The integral of 2e^{5sin(3x)}cos(3x) is 2/15 e^{5sin(3x)}+C