What is the integral of 1/(2sin(θ))*(-2sin(θ)) ?

The integral of 1/(2sin(θ))*(-2sin(θ)) is -θ+C

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integral of 1/(2sin(θ))*(-2sin(θ))

\int \frac{1}{2 sin ( θ )} \cdot (- 2 sin (θ)) d θ

- θ + C

Solution steps

\int \frac{1}{2 sin ( θ )} (- 2 sin (θ)) d θ

\frac{1}{2 sin ( θ )} (- 2 sin (θ)) = - 1

= \int - 1 d θ

Integral of a constant:

\int a d x = a x

= (- 1) θ

Simplify

= - θ

Add a constant to the solution

= - θ + C

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What is the integral of 1/(2sin(θ))*(-2sin(θ)) ?
The integral of 1/(2sin(θ))*(-2sin(θ)) is -θ+C