What is the integral of (2/x+sec^2(x)) ?

The integral of (2/x+sec^2(x)) is 2ln|x|+tan(x)+C

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral of (2/x+sec^2(x))

\int (\frac{2}{x} + sec^{2} (x)) d x

2 ln ∣ x ∣ + tan (x) + C

Solution steps

\int \frac{2}{x} + sec^{2} (x) d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int \frac{2}{x} d x + \int sec^{2} (x) d x

\int \frac{2}{x} d x = 2 ln ∣ x ∣

\int sec^{2} (x) d x = tan (x)

= 2 ln ∣ x ∣ + tan (x)

Add a constant to the solution

= 2 ln ∣ x ∣ + tan (x) + C

\int \frac{1}{u + u ^{2}} d u

\int sin (10 w) d w

\int \frac{1}{( x ^{2} + a ^{2} )} d x

\int \frac{1}{x cos ( 1 - x )} d x

\int \frac{x ^{7}}{x ^{4} + 1} d x

What is the integral of (2/x+sec^2(x)) ?
The integral of (2/x+sec^2(x)) is 2ln|x|+tan(x)+C