integral from 1 to infinity of x/(x^2+9)

Lösung

\int_{1}^{\infty} \frac{x}{x ^{2} + 9} d x

divergiert

Schritte zur Lösung

\int_{1}^{\infty} \frac{x}{x ^{2} + 9} d x

Berechne das unbestimmte Integral:

\int \frac{x}{x ^{2} + 9} d x = \frac{1}{2} ln x^{2} + 9 + C

Berechne die Grenzen:

\int_{1}^{\infty} \frac{x}{x ^{2} + 9} d x =

divergiert

= divergiert

\int_{0}^{1} (1 - x^{4})^{10} d x

\int_{1}^{4} \frac{1}{x ^{3}} ln (6 x) d x

\int_{- \infty}^{1} 6 - x d x

\int_{1}^{e} (ln (x))^{10} d x

\int_{0}^{1} (1 - x^{4})^{11} d x