What is the integral from-3 to 4 of (cos(x)-3/(x^5)) ?

The integral from-3 to 4 of (cos(x)-3/(x^5)) is diverges

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integral from-3 to 4 of (cos(x)-3/(x^5))

\int_{- 3}^{4} (cos (x) - \frac{3}{x ^{5}}) d x

diverges

Solution steps

\int_{- 3}^{4} cos (x) - \frac{3}{x ^{5}} d x

Find undefined (singularity) points:

x = 0

If exist

b, a < b < c, f (b) =

undefined

, \int_{a}^{c} f (x) d x = \int_{a}^{b} f (x) d x + \int_{b}^{c} f (x) d x

= \int_{- 3}^{0} cos (x) - \frac{3}{x ^{5}} d x + \int_{0}^{4} cos (x) - \frac{3}{x ^{5}} d x

\int_{- 3}^{0} cos (x) - \frac{3}{x ^{5}} d x =

diverges

If part of the expression diverges, then entire expression diverges

= diverges

\int_{2}^{3} \frac{2 x ^{2}}{x ^{2} - 1} d x

\int_{0}^{1} e^{1 - x} cos (2 x) d x

\int_{- 1}^{1} \frac{8 x}{x ^{2} + 4} d x

\int_{1}^{13} (6 x^{2} + 3 x - 2) d x

What is the integral from-3 to 4 of (cos(x)-3/(x^5)) ?
The integral from-3 to 4 of (cos(x)-3/(x^5)) is diverges