integral from 0 to 3 of sin(x+1)

解答

\int_{0}^{3} sin (x + 1) d x

- cos (4) + cos (1)

十进制

1.19394 \dots

求解步骤

\int_{0}^{3} sin (x + 1) d x

使用换元积分法

= \int_{1}^{4} sin (u) d u

使用积分常见定则:

\int sin (u) d u = - cos (u)

= [- cos (u)]_{1}^{4}

带入上下限计算后得:

- cos (4) + cos (1)

= - cos (4) + cos (1)

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