integral from 0 to 1 of (x+2)^3

Lösung

\int_{0}^{1} (x + 2)^{3} d x

\frac{65}{4}

Dezimale

16.25

Schritte zur Lösung

\int_{0}^{1} (x + 2)^{3} d x

Wende U-Substitution an

= \int_{2}^{3} u^{3} d u

Wende die Potenzregel an

= [\frac{u ^{4}}{4}]_{2}^{3}

Berechne die Grenzen:

\frac{65}{4}

= \frac{65}{4}

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