ja

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

人気のある微分積分 >

integral from 0 to 1 of x*sin(x)

解

\int_{0}^{1} x \cdot sin (x) d x

解

sin (1) - cos (1)

+1

十進法表記

0.30116 \dots

解答ステップ

\int_{0}^{1} x sin (x) d x

部分積分を適用する

= [- x cos (x) - \int - cos (x) d x]_{0}^{1}

\int - cos (x) d x = - sin (x)

= [- x cos (x) - (- sin (x))]_{0}^{1}

簡素化

= [- x cos (x) + sin (x)]_{0}^{1}

限度を計算する:

sin (1) - cos (1)

= sin (1) - cos (1)

グラフ

人気の例

integral from 0.5 to 1 of cos(pi)xln(x)

\int_{0.5}^{1} cos (π) x ln (x) d x

integral from 0 to 1 of y^3e^{y^4}

\int_{0}^{1} y^{3} e^{y^{4}} d y

integral from-1 to 1 of cx^2

\int_{- 1}^{1} c x^{2} d x

integral from-1 to 0 of 2(e^{1/x})/(x^3)

\int_{- 1}^{0} 2 \frac{e ^{\frac{1}{x}}}{x ^{3}} d x

integral from-1 to 1 of-4x^2+3x-2

\int_{- 1}^{1} - 4 x^{2} + 3 x - 2 d x