integral from-4 to 0 of (x+1)

Lösung

\int_{- 4}^{0} (x + 1) d x

- 4

Schritte zur Lösung

\int_{- 4}^{0} x + 1 d x

Wende die Summenregel an:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{- 4}^{0} x d x + \int_{- 4}^{0} 1 d x

\int_{- 4}^{0} x d x = - 8

\int_{- 4}^{0} 1 d x = 4

= - 8 + 4

Vereinfache

= - 4

\int_{- \infty}^{- 2} \frac{1}{1 - x} d x

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