What is the integral from 0 to 1 of tan(pix) ?

The integral from 0 to 1 of tan(pix) is diverges

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integral from 0 to 1 of tan(pix)

\int_{0}^{1} tan (π x) d x

diverges

Solution steps

\int_{0}^{1} tan (π x) d x

Take the denominator(s) of

tan (π x)

and compare to zero:

x = \frac{1}{2}

If exist

b, a < b < c, f (b) =

undefined

, \int_{a}^{c} f (x) d x = \int_{a}^{b} f (x) d x + \int_{b}^{c} f (x) d x

= \int_{0}^{\frac{1}{2}} tan (π x) d x + \int_{\frac{1}{2}}^{1} tan (π x) d x

\int_{0}^{\frac{1}{2}} tan (π x) d x =

diverges

If part of the expression diverges, then entire expression diverges

= diverges

\int_{\frac{π}{2}}^{π} \frac{1 + cos ( x )}{x} d x

\int_{1}^{3} (\frac{1}{x} - y) d x

\int_{0}^{\frac{π}{2}} cos (9 x) cos (18 x) d x

\int_{1}^{3} x^{5} ln (x) d x

\int_{0}^{4} (4 x^{2} + x y - 2 y^{2}) d x

What is the integral from 0 to 1 of tan(pix) ?
The integral from 0 to 1 of tan(pix) is diverges