integral from 0 to 1 of x(4x^3)

Lösung

\int_{0}^{1} x (4 x^{3}) d x

\frac{4}{5}

Dezimale

0.8

Schritte zur Lösung

\int_{0}^{1} x \cdot 4 x^{3} d x

Entferne die Konstante:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 4 \cdot \int_{0}^{1} x x^{3} d x

Vereinfache

x x^{3} : x^{4}

= 4 \cdot \int_{0}^{1} x^{4} d x

Wende die Potenzregel an

= 4 [\frac{x ^{5}}{5}]_{0}^{1}

Berechne die Grenzen:

\frac{1}{5}

= 4 \cdot \frac{1}{5}

Vereinfache

= \frac{4}{5}

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