integral from 1 to 4 of 6x^2-4x+1

Lösung

\int_{1}^{4} 6 x^{2} - 4 x + 1 d x

99

Schritte zur Lösung

\int_{1}^{4} 6 x^{2} - 4 x + 1 d x

Wende die Summenregel an:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{1}^{4} 6 x^{2} d x - \int_{1}^{4} 4 x d x + \int_{1}^{4} 1 d x

\int_{1}^{4} 6 x^{2} d x = 126

\int_{1}^{4} 4 x d x = 30

\int_{1}^{4} 1 d x = 3

= 126 - 30 + 3

Vereinfache

= 99

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