integral from 1 to 2 of (x^2+4)

Lösung

\int_{1}^{2} (x^{2} + 4) d x

\frac{19}{3}

Dezimale

6.33333 \dots

Schritte zur Lösung

\int_{1}^{2} x^{2} + 4 d x

Wende die Summenregel an:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{1}^{2} x^{2} d x + \int_{1}^{2} 4 d x

\int_{1}^{2} x^{2} d x = \frac{7}{3}

\int_{1}^{2} 4 d x = 4

= \frac{7}{3} + 4

Vereinfache

\frac{7}{3} + 4 : \frac{19}{3}

= \frac{19}{3}

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