integral from 0 to 3 of x^2-6x+8

Lösung

\int_{0}^{3} x^{2} - 6 x + 8 d x

6

Schritte zur Lösung

\int_{0}^{3} x^{2} - 6 x + 8 d x

Wende die Summenregel an:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{0}^{3} x^{2} d x - \int_{0}^{3} 6 x d x + \int_{0}^{3} 8 d x

\int_{0}^{3} x^{2} d x = 9

\int_{0}^{3} 6 x d x = 27

\int_{0}^{3} 8 d x = 24

= 9 - 27 + 24

Vereinfache

= 6

\int_{0}^{3} t^{2} d t

\int_{0}^{4} 8 y d y

\int_{i}^{1} (z + 1)^{2} d z

\int_{1}^{\infty} \frac{1}{n ^{2} + 1}

\int_{0}^{π} - x sin (x^{2}) d x