What is the integral from x to 1 of e^{y^2} ?

The integral from x to 1 of e^{y^2} is (sqrt(pi))/2 \erfi(1)-(sqrt(pi))/2 \erfi(x)

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integral from x to 1 of e^{y^2}

\int_{x}^{1} e^{y^{2}} d y

\frac{π}{2} erfi (1) - \frac{π}{2} erfi (x)

Solution steps

\int_{x}^{1} e^{y^{2}} d y

Use the nonelementary integral:

\int e^{y^{2}} d y = \frac{π}{2} erfi (y)

= [\frac{π}{2} erfi (y)]_{x}^{1}

Compute the boundaries:

\frac{π}{2} erfi (1) - \frac{π}{2} erfi (x)

= \frac{π}{2} erfi (1) - \frac{π}{2} erfi (x)

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What is the integral from x to 1 of e^{y^2} ?
The integral from x to 1 of e^{y^2} is (sqrt(pi))/2 \erfi(1)-(sqrt(pi))/2 \erfi(x)