integral from 0 to 1 of t^2+2

Lösung

\int_{0}^{1} t^{2} + 2 d t

\frac{7}{3}

Dezimale

2.33333 \dots

Schritte zur Lösung

\int_{0}^{1} t^{2} + 2 d t

Wende die Summenregel an:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{0}^{1} t^{2} d t + \int_{0}^{1} 2 d t

\int_{0}^{1} t^{2} d t = \frac{1}{3}

\int_{0}^{1} 2 d t = 2

= \frac{1}{3} + 2

Vereinfache

\frac{1}{3} + 2 : \frac{7}{3}

= \frac{7}{3}

\int_{y}^{y} 1 d x

\int_{0}^{2} \frac{1}{6} x d x

\int_{1}^{4} \frac{1}{6} (x - 1) d x

\int_{25}^{40} \frac{1}{15} x^{2} d x

\int_{- 1}^{1} (- 1 + 2 t^{2})^{3} d t