What is the integral from-infinity to 0 of e^{2x+1} ?

The integral from-infinity to 0 of e^{2x+1} is e/2

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integral from-infinity to 0 of e^{2x+1}

\int_{- \infty}^{0} e^{2 x + 1} d x

\frac{e}{2}

Decimal Notation

1.35914 \dots

Solution steps

\int_{- \infty}^{0} e^{2 x + 1} d x

Compute the indefinite integral:

\int e^{2 x + 1} d x = \frac{1}{2} e^{2 x + 1} + C

Compute the boundaries:

\int_{- \infty}^{0} e^{2 x + 1} d x = \frac{e}{2} - 0

= \frac{e}{2} - 0

Simplify

= \frac{e}{2}

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What is the integral from-infinity to 0 of e^{2x+1} ?
The integral from-infinity to 0 of e^{2x+1} is e/2