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人気のある微分積分 >

integral from 0 to 1 of 0.2+cy

解

\int_{0}^{1} 0.2 + cy d y

解

0.2 + 0.5 c

解答ステップ

\int_{0}^{1} 0.2 + cy d y

総和規則を適用する:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{0}^{1} 0.2 d y + \int_{0}^{1} cy d y

\int_{0}^{1} 0.2 d y = 0.2

\int_{0}^{1} cy d y = \frac{c}{2}

= 0.2 + \frac{c}{2}

簡素化

= 0.2 + 0.5 c

人気の例

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\int_{1}^{e^{π}} cos (ln (x)) d x

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