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人気のある微分積分 >

integral from 0 to 3 of 3x(1+3x^2)^2

解

\int_{0}^{3} 3 x (1 + 3 x^{2})^{2} d x

解

\frac{7317}{2}

+1

十進法表記

3658.5

解答ステップ

\int_{0}^{3} 3 x (1 + 3 x^{2})^{2} d x

定数を除く:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 3 \cdot \int_{0}^{3} x (1 + 3 x^{2})^{2} d x

u置換積分法を適用する

= 3 \cdot \int_{1}^{28} \frac{u ^{2}}{6} d u

定数を除く:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 3 \cdot \frac{1}{6} \cdot \int_{1}^{28} u^{2} d u

べき乗則を適用する

= 3 \cdot \frac{1}{6} [\frac{u ^{3}}{3}]_{1}^{28}

簡素化

3 \cdot \frac{1}{6} [\frac{u ^{3}}{3}]_{1}^{28} : \frac{1}{2} [\frac{u ^{3}}{3}]_{1}^{28}

= \frac{1}{2} [\frac{u ^{3}}{3}]_{1}^{28}

限度を計算する:

7317

= \frac{1}{2} \cdot 7317

簡素化

= \frac{7317}{2}

グラフ

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