integral from 0 to 2pi of (t)^2

Lösung

\int_{0}^{2 π} (t)^{2} d t

\frac{8 π ^{3}}{3}

Dezimale

82.68340 \dots

Schritte zur Lösung

\int_{0}^{2 π} t^{2} d t

Wende die Potenzregel an

= [\frac{t ^{3}}{3}]_{0}^{2 π}

Berechne die Grenzen:

\frac{8 π ^{3}}{3}

= \frac{8 π ^{3}}{3}

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