integral from 0 to 2 of 1/(t-2)

Lösung

\int_{0}^{2} \frac{1}{t - 2} d t

divergiert

Schritte zur Lösung

\int_{0}^{2} \frac{1}{t - 2} d t

Wende U-Substitution an

= \int_{- 2}^{0} \frac{1}{u} d u

Nutze das gemeinsame Integral :

\int \frac{1}{u} d u = ln (∣ u ∣)

= [ln ∣ u ∣]_{- 2}^{0}

Berechne die Grenzen:

divergiert

= divergiert

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