integral from 0 to 4 of sqrt(xy)

Lösung

\int_{0}^{4} x y d x

\frac{16 y}{3}

Schritte zur Lösung

\int_{0}^{4} x y d x

y x = y x

= \int_{0}^{4} y x d x

Entferne die Konstante:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= y \cdot \int_{0}^{4} x d x

Wende die Potenzregel an

= y [\frac{2}{3} x^{\frac{3}{2}}]_{0}^{4}

Berechne die Grenzen:

\frac{16}{3}

= y \frac{16}{3}

Vereinfache

= \frac{16 y}{3}

\int_{0}^{1} ln (x + 2) d x

\int_{2}^{4} \frac{2 x ^{2}}{x + 2} d x

\int_{7}^{13} 4 x^{5} d x

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\int_{1}^{5} \frac{5 ^{l n (x)}}{x} d x