integral from 0 to 1 of (1+e^x)

Lösung

\int_{0}^{1} (1 + e^{x}) d x

e

Dezimale

2.71828 \dots

Schritte zur Lösung

\int_{0}^{1} 1 + e^{x} d x

Wende die Summenregel an:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{0}^{1} 1 d x + \int_{0}^{1} e^{x} d x

\int_{0}^{1} 1 d x = 1

\int_{0}^{1} e^{x} d x = e - 1

= 1 + e - 1

Vereinfache

= e

\int_{0}^{1} \frac{x ^{3} + 1}{9} d x

\int_{+ 0}^{9} \frac{1}{( x - 1 ) ^{\frac{1}{3}}} d x

\int_{2}^{5} 4 x + 3 d x

\int_{3}^{8} 3 x^{3} d x

\int_{- 2}^{1} (3 x^{3} - 2 x^{2} + x) d x