integral from 1 to 5 of-x^2+4x

Lösung

\int_{1}^{5} - x^{2} + 4 x d x

\frac{20}{3}

Dezimale

6.66666 \dots

Schritte zur Lösung

\int_{1}^{5} - x^{2} + 4 x d x

Wende die Summenregel an:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= - \int_{1}^{5} x^{2} d x + \int_{1}^{5} 4 x d x

\int_{1}^{5} x^{2} d x = \frac{124}{3}

\int_{1}^{5} 4 x d x = 48

= - \frac{124}{3} + 48

Vereinfache

- \frac{124}{3} + 48 : \frac{20}{3}

= \frac{20}{3}

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