integral from 0 to 3 of e^{-st}

Lösung

\int_{0}^{3} e^{- s t} d t

- \frac{e ^{- 3 s} - 1}{s}

Schritte zur Lösung

\int_{0}^{3} e^{- s t} d t

Wende U-Substitution an

= \int_{0}^{- s \cdot 3} - \frac{e ^{u}}{s} d u

Entferne die Konstante:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= - \frac{1}{s} \cdot \int_{0}^{- s \cdot 3} e^{u} d u

Nutze das gemeinsame Integral :

\int e^{u} d u = e^{u}

= - \frac{1}{s} [e^{u}]_{0}^{- s \cdot 3}

Vereinfache

- \frac{1}{s} [e^{u}]_{0}^{- s \cdot 3} : - \frac{[ e ^{u} ] _{0}^{- 3 s}}{s}

= - \frac{[ e ^{u} ] _{0}^{- 3 s}}{s}

Berechne die Grenzen:

e^{- 3 s} - 1

= - \frac{e ^{- 3 s} - 1}{s}

\int_{0}^{3} (x - 5)^{3} d x

\int_{- 2}^{2} 9 - x^{2} d x

\int_{0.5}^{0.9} 0.0014400000000 \dots x d x

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\int_{0}^{2} (x - 3 x^{2})^{3} d x