integral from 0 to 5 of y

Lösung

\int_{0}^{5} y d y

\frac{25}{2}

Dezimale

12.5

Schritte zur Lösung

\int_{0}^{5} y d y

Wende die Potenzregel an

= [\frac{y ^{2}}{2}]_{0}^{5}

Berechne die Grenzen:

\frac{25}{2}

= \frac{25}{2}

\int_{- 4}^{\infty} \frac{1}{x + 6} d x

\int_{0}^{1} x^{2} 3 1 - x d x

\int_{0}^{1} \frac{1}{1 - cos ( x )} d x

\int_{- 3}^{5} \frac{1}{( x - 2 ) ^{3}} d x

\int_{2}^{5} \frac{1}{3 u + 7} d u