integral from 0 to 2 of (4-x-y)

Lösung

\int_{0}^{2} (4 - x - y) d y

- 2 x + 6

Schritte zur Lösung

\int_{0}^{2} 4 - x - y d y

Wende die Summenregel an:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{0}^{2} 4 d y - \int_{0}^{2} x d y - \int_{0}^{2} y d y

\int_{0}^{2} 4 d y = 8

\int_{0}^{2} x d y = 2 x

\int_{0}^{2} y d y = 2

= 8 - 2 x - 2

Vereinfache

= - 2 x + 6

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