integral from y-1 to 1-y of x

Lösung

\int_{y - 1}^{1 - y} x d x

0

Schritte zur Lösung

\int_{y - 1}^{1 - y} x d x

Wende die Potenzregel an

= [\frac{x ^{2}}{2}]_{- 1 + y}^{1 - y}

Berechne die Grenzen:

\frac{( 1 - y ) ^{2}}{2} - \frac{( - 1 + y ) ^{2}}{2}

= \frac{( 1 - y ) ^{2}}{2} - \frac{( - 1 + y ) ^{2}}{2}

Vereinfache

= 0

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