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人気のある微分積分 >

integral from 0 to 18 of x(1/162 x)

解

\int_{0}^{18} x (\frac{1}{162} x) d x

解

12

解答ステップ

\int_{0}^{18} x \frac{1}{162} x d x

定数を除く:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= \frac{1}{162} \cdot \int_{0}^{18} xx d x

簡素化

xx : x^{2}

= \frac{1}{162} \cdot \int_{0}^{18} x^{2} d x

べき乗則を適用する

= \frac{1}{162} [\frac{x ^{3}}{3}]_{0}^{18}

限度を計算する:

1944

= \frac{1}{162} \cdot 1944

簡素化

= 12

グラフ

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