integral from 1 to 5 of (x^2+1)

Lösung

\int_{1}^{5} (x^{2} + 1) d x

\frac{136}{3}

Dezimale

45.33333 \dots

Schritte zur Lösung

\int_{1}^{5} x^{2} + 1 d x

Wende die Summenregel an:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{1}^{5} x^{2} d x + \int_{1}^{5} 1 d x

\int_{1}^{5} x^{2} d x = \frac{124}{3}

\int_{1}^{5} 1 d x = 4

= \frac{124}{3} + 4

Vereinfache

\frac{124}{3} + 4 : \frac{136}{3}

= \frac{136}{3}

\int_{- 1}^{3} x^{3} - 3 x^{2} - 1 d x

\int_{0}^{2} \frac{x}{4 4 - x ^{2}} d x

\int_{- 1}^{2} (3 x^{2} - 2) d x

\int_{0}^{3} y e^{- x y} d y

\int_{0}^{5} \frac{2 x ^{2}}{25} d x