integral from 0.2 to 0.8 of 2x

Lösung

\int_{0.2}^{0.8} 2 x d x

0.6

Schritte zur Lösung

\int_{0.2}^{0.8} 2 x d x

Entferne die Konstante:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 2 \cdot \int_{0.2}^{0.8} x d x

Wende die Potenzregel an

= 2 [\frac{x ^{2}}{2}]_{0.2}^{0.8}

Vereinfache

= 2 [0.5 x^{2}]_{0.2}^{0.8}

Berechne die Grenzen:

0.3

= 2 \cdot 0.3

Vereinfache

= 0.6

\int_{1}^{2} \frac{1}{x ( ln ( x ) )} d x

\int_{1}^{π} ln (t) d t

\int_{0}^{18} x^{2} d x

\int_{1}^{1} x ln (x) d x

\int_{0}^{1} 2 x x + 1 d x