integral from 1 to pi of ln(t)

Lösung

\int_{1}^{π} ln (t) d t

π ln (π) - π + 1

Dezimale

1.45468 \dots

Schritte zur Lösung

\int_{1}^{π} ln (t) d t

Wende die partielle Integration an

= [t ln (t) - \int 1 d t]_{1}^{π}

\int 1 d t = t

= [t ln (t) - t]_{1}^{π}

Berechne die Grenzen:

π ln (π) - π + 1

= π ln (π) - π + 1

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