integral from 1 to 3 of (4x-x^2-3)

Lösung

\int_{1}^{3} (4 x - x^{2} - 3) d x

\frac{4}{3}

Dezimale

1.33333 \dots

Schritte zur Lösung

\int_{1}^{3} 4 x - x^{2} - 3 d x

Wende die Summenregel an:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{1}^{3} 4 x d x - \int_{1}^{3} x^{2} d x - \int_{1}^{3} 3 d x

\int_{1}^{3} 4 x d x = 16

\int_{1}^{3} x^{2} d x = \frac{26}{3}

\int_{1}^{3} 3 d x = 6

= 16 - \frac{26}{3} - 6

Vereinfache

16 - \frac{26}{3} - 6 : \frac{4}{3}

= \frac{4}{3}

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