integral from 0 to pi of 18cos(6x)+6yz^2

Lösung

\int_{0}^{π} 18 cos (6 x) + 6 y z^{2} d x

6 π y z^{2}

Schritte zur Lösung

\int_{0}^{π} 18 cos (6 x) + 6 y z^{2} d x

Wende die Summenregel an:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{0}^{π} 18 cos (6 x) d x + \int_{0}^{π} 6 y z^{2} d x

\int_{0}^{π} 18 cos (6 x) d x = 0

\int_{0}^{π} 6 y z^{2} d x = 6 π y z^{2}

= 0 + 6 π y z^{2}

Vereinfache

= 6 π y z^{2}

\int_{0}^{1} (4 x - e^{- x}) d x

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\int_{0}^{\frac{π}{2}} (1 + cos (θ))^{2} d θ

\int_{- 3}^{- 2} \frac{2 - x}{32} d x