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人気のある微分積分 >

integral from 0 to 1 of ((x-1)/(x+1))^3

解

\int_{0}^{1} (\frac{x - 1}{x + 1})^{3} d x

解

\frac{- 96 ln ( 2 ) + 64}{16}

+1

十進法表記

- 0.15888 \dots

解答ステップ

\int_{0}^{1} (\frac{x - 1}{x + 1})^{3} d x

拡張

(\frac{x - 1}{x + 1})^{3} : \frac{x ^{3} - 3 x ^{2} + 3 x - 1}{x ^{3} + 3 x ^{2} + 3 x + 1}

= \int_{0}^{1} \frac{x ^{3} - 3 x ^{2} + 3 x - 1}{x ^{3} + 3 x ^{2} + 3 x + 1} d x

拡張

\frac{x ^{3} - 3 x ^{2} + 3 x - 1}{x ^{3} + 3 x ^{2} + 3 x + 1} : \frac{x ^{3}}{x ^{3} + 3 x ^{2} + 3 x + 1} - \frac{3 x ^{2}}{x ^{3} + 3 x ^{2} + 3 x + 1} + \frac{3 x}{x ^{3} + 3 x ^{2} + 3 x + 1} - \frac{1}{x ^{3} + 3 x ^{2} + 3 x + 1}

総和規則を適用する:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{0}^{1} \frac{x ^{3}}{x ^{3} + 3 x ^{2} + 3 x + 1} d x - \int_{0}^{1} \frac{3 x ^{2}}{x ^{3} + 3 x ^{2} + 3 x + 1} d x + \int_{0}^{1} \frac{3 x}{x ^{3} + 3 x ^{2} + 3 x + 1} d x - \int_{0}^{1} \frac{1}{x ^{3} + 3 x ^{2} + 3 x + 1} d x

\int_{0}^{1} \frac{x ^{3}}{x ^{3} + 3 x ^{2} + 3 x + 1} d x = \frac{- 48 ln ( 2 ) - 54}{16} + \frac{11}{2}

\int_{0}^{1} \frac{3 x ^{2}}{x ^{3} + 3 x ^{2} + 3 x + 1} d x = 3 (\frac{16 ln ( 2 ) + 30}{16} - \frac{5}{2})

\int_{0}^{1} \frac{3 x}{x ^{3} + 3 x ^{2} + 3 x + 1} d x = \frac{3}{8}

\int_{0}^{1} \frac{1}{x ^{3} + 3 x ^{2} + 3 x + 1} d x = \frac{3}{8}

= \frac{- 48 ln ( 2 ) - 54}{16} + \frac{11}{2} - 3 (\frac{16 ln ( 2 ) + 30}{16} - \frac{5}{2}) + \frac{3}{8} - \frac{3}{8}

簡素化

\frac{- 48 ln ( 2 ) - 54}{16} + \frac{11}{2} - 3 (\frac{16 ln ( 2 ) + 30}{16} - \frac{5}{2}) + \frac{3}{8} - \frac{3}{8} : \frac{- 96 ln ( 2 ) + 64}{16}

= \frac{- 96 ln ( 2 ) + 64}{16}

グラフ

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