integral from 0 to t of (t+2)

Lösung

\int_{0}^{t} (t + 2) d t

\frac{t ^{2}}{2} + 2 t

Schritte zur Lösung

\int_{0}^{t} t + 2 d t

Wende die Summenregel an:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{0}^{t} t d t + \int_{0}^{t} 2 d t

\int_{0}^{t} t d t = \frac{t ^{2}}{2}

\int_{0}^{t} 2 d t = 2 t

= \frac{t ^{2}}{2} + 2 t

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