integral from 0 to 2 of sqrt(7x+1)

Lösung

\int_{0}^{2} 7 x + 1 d x

\frac{30 15 - 2}{21}

Dezimale

5.43759 \dots

Schritte zur Lösung

\int_{0}^{2} 7 x + 1 d x

Wende U-Substitution an

= \int_{1}^{15} \frac{u}{7} d u

Entferne die Konstante:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= \frac{1}{7} \cdot \int_{1}^{15} u d u

Wende die Potenzregel an

= \frac{1}{7} [\frac{2}{3} u^{\frac{3}{2}}]_{1}^{15}

Berechne die Grenzen:

1015 - \frac{2}{3}

= \frac{1}{7} (1015 - \frac{2}{3})

Vereinfache

= \frac{30 15 - 2}{21}

\int_{1}^{5} \frac{3}{3 x - 2} d x

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