integral from 1 to 3 of (-x^2+4)

Lösung

\int_{1}^{3} (- x^{2} + 4) d x

- \frac{2}{3}

Dezimale

- 0.66666 \dots

Schritte zur Lösung

\int_{1}^{3} - x^{2} + 4 d x

Wende die Summenregel an:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= - \int_{1}^{3} x^{2} d x + \int_{1}^{3} 4 d x

\int_{1}^{3} x^{2} d x = \frac{26}{3}

\int_{1}^{3} 4 d x = 8

= - \frac{26}{3} + 8

Vereinfache

- \frac{26}{3} + 8 : - \frac{2}{3}

= - \frac{2}{3}

\int_{0}^{3} x^{3} e^{x^{2}} d x

\int_{1}^{6} x^{3} d x

\int_{2}^{\infty} \frac{e ^{x}}{x} d x

\int_{2}^{5} x^{2} + \frac{1}{x ^{2}} d x

\int_{- 1}^{3} ∣ 2 x ∣ d x