integral from x-1 to sqrt(2x+6 of)xy

Lösung

\int_{x - 1}^{2 x + 6} x y d y

x (3 + x - \frac{( - 1 + x ) ^{2}}{2})

Schritte zur Lösung

\int_{x - 1}^{2 x + 6} x y d y

Entferne die Konstante:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= x \cdot \int_{- 1 + x}^{6 + 2 x} y d y

Wende die Potenzregel an

= x [\frac{y ^{2}}{2}]_{- 1 + x}^{6 + 2 x}

Berechne die Grenzen:

3 + x - \frac{( - 1 + x ) ^{2}}{2}

= x (3 + x - \frac{( - 1 + x ) ^{2}}{2})

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