sum from k=1 to infinity of 1/(sqrt(k))

Lösung

k = 1 \sum \infty \frac{1}{k}

divergiert

Schritte zur Lösung

k = 1 \sum \infty \frac{1}{k}

p-Reihen-Test anwenden:

divergiert

= divergiert

n = 1 \sum \infty \frac{n - 1}{7 n - 1}

n = 0 \sum \infty \frac{n + 1}{2 n}

n = 3 \sum \infty \frac{1}{n ( n + 2 )}

n = 0 \sum \infty \frac{1}{ln ( n ^{2} )}

n = 0 \sum \infty (\frac{i}{1 + i})^{n}