What is the sum from k=0 to infinity of (0.6)^k ?

The sum from k=0 to infinity of (0.6)^k is 2.5

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sum from k=0 to infinity of (0.6)^k

k = 0 \sum \infty (0.6)^{k}

2.5

Solution steps

k = 0 \sum \infty 0. 6^{k}

Apply Series Geometric Test:

2.5

= 2.5

n = 1 \sum \infty \frac{n ^{2}}{7 ^{n}}

n = 0 \sum \infty \frac{4}{2 n + 3}

n = 0 \sum \infty 9^{- n}

n = 2 \sum \infty \frac{1}{n ln ( n ^{3} )}

n = 0 \sum \infty \frac{i}{n !}

What is the sum from k=0 to infinity of (0.6)^k ?
The sum from k=0 to infinity of (0.6)^k is 2.5